How many moles of ferric acetate would be needed to completely react with all of the strontium hydroxide?

According to the equation, every mole of Strontium hydroxide will react with 2/3 of a mole of Ferric acetate. The number of moles of Strontium hydroxide are 2.62 moles/liter times 0.480 liters = 1.26 moles. 2/3 times 1.26 moles is the amount of Ferric acetate needed. The amount of iron added is 3 moles/liter times 0.320 liters = 0.96 moles. According to the calculations, 0.832 moles of Ferric acetate will be needed. The number of moles of ferric acetate and Ferric hydroxide are the same, so 0.832 moles of Fe(OH)3 is the maximum yield. The molecular weight of Fe(OH)3 is 54 + 48 + 3 = 105 grams per mole. uming the precipitate is Fe(OH)3, 60 grams will be 0.571 moles. 0.571 moiles / 0.832 moles = 69 % recovery.